Exercise 1.6, Question 1

The frequency of
tasters (TT or Tt) is 352/550 = 0.64 = 64%.
Therefore, the frequency of
nontasters (tt) = 1  0.64, or 36%.
If the frequency of tt = .36, then the frequency of t,
the nontasting allele = the square root of 0.36 = 0.6,
and T = 1  0.6 = 0.4

Frequency of Homozygous tasters (TT): p^{2} =
(.4)^{2 }= 0.16
Frequency of Heterozygotes (Tt): 2pq = 2(.4)(.6) = 0.48
Frequency of Homozygous nontasters (tt): q^{2} = (.6)^{2} = 0.36
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